Optimal. Leaf size=200 \[ -\frac{2 \left (\sqrt{-a}-\sqrt{c} x\right ) \sqrt [4]{-\frac{\left (\sqrt{-a}+\sqrt{c} x\right ) \left (\sqrt{-a} e+\sqrt{c} d\right )}{\left (\sqrt{-a}-\sqrt{c} x\right ) \left (\sqrt{c} d-\sqrt{-a} e\right )}} \, _2F_1\left (-\frac{1}{2},\frac{1}{4};\frac{1}{2};\frac{2 \sqrt{-a} \sqrt{c} (d+e x)}{\left (\sqrt{c} d-\sqrt{-a} e\right ) \left (\sqrt{-a}-\sqrt{c} x\right )}\right )}{\sqrt [4]{a+c x^2} \sqrt{d+e x} \left (\sqrt{-a} e+\sqrt{c} d\right )} \]
[Out]
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Rubi [A] time = 0.234135, antiderivative size = 200, normalized size of antiderivative = 1., number of steps used = 1, number of rules used = 1, integrand size = 21, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.048 \[ -\frac{2 \left (\sqrt{-a}-\sqrt{c} x\right ) \sqrt [4]{-\frac{\left (\sqrt{-a}+\sqrt{c} x\right ) \left (\sqrt{-a} e+\sqrt{c} d\right )}{\left (\sqrt{-a}-\sqrt{c} x\right ) \left (\sqrt{c} d-\sqrt{-a} e\right )}} \, _2F_1\left (-\frac{1}{2},\frac{1}{4};\frac{1}{2};\frac{2 \sqrt{-a} \sqrt{c} (d+e x)}{\left (\sqrt{c} d-\sqrt{-a} e\right ) \left (\sqrt{-a}-\sqrt{c} x\right )}\right )}{\sqrt [4]{a+c x^2} \sqrt{d+e x} \left (\sqrt{-a} e+\sqrt{c} d\right )} \]
Antiderivative was successfully verified.
[In] Int[1/((d + e*x)^(3/2)*(a + c*x^2)^(1/4)),x]
[Out]
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Rubi in Sympy [A] time = 11.6014, size = 167, normalized size = 0.84 \[ - \frac{2 \sqrt [4]{\frac{\left (\sqrt{c} d + e \sqrt{- a}\right ) \left (\sqrt{c} x + \sqrt{- a}\right )}{\left (\sqrt{c} d - e \sqrt{- a}\right ) \left (\sqrt{c} x - \sqrt{- a}\right )}} \left (- \sqrt{c} x + \sqrt{- a}\right ){{}_{2}F_{1}\left (\begin{matrix} - \frac{1}{2}, \frac{1}{4} \\ \frac{1}{2} \end{matrix}\middle |{\frac{2 \sqrt{c} \sqrt{- a} \left (d + e x\right )}{\left (\sqrt{c} d - e \sqrt{- a}\right ) \left (- \sqrt{c} x + \sqrt{- a}\right )}} \right )}}{\sqrt [4]{a + c x^{2}} \sqrt{d + e x} \left (\sqrt{c} d + e \sqrt{- a}\right )} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] rubi_integrate(1/(e*x+d)**(3/2)/(c*x**2+a)**(1/4),x)
[Out]
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Mathematica [C] time = 1.58723, size = 171, normalized size = 0.86 \[ \frac{2\ 2^{3/4} \left (\sqrt{c} x+i \sqrt{a}\right ) \sqrt [4]{\frac{\frac{i \sqrt{c} d x}{\sqrt{a}}-\frac{i \sqrt{a} e}{\sqrt{c}}+d+e x}{d+e x}} \, _2F_1\left (\frac{1}{4},\frac{3}{4};\frac{7}{4};\frac{-\frac{i \sqrt{c} x d}{\sqrt{a}}+d+\frac{i \sqrt{a} e}{\sqrt{c}}+e x}{2 d+2 e x}\right )}{3 \sqrt [4]{a+c x^2} \sqrt{d+e x} \left (\sqrt{c} d-i \sqrt{a} e\right )} \]
Antiderivative was successfully verified.
[In] Integrate[1/((d + e*x)^(3/2)*(a + c*x^2)^(1/4)),x]
[Out]
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Maple [F] time = 0.088, size = 0, normalized size = 0. \[ \int{1 \left ( ex+d \right ) ^{-{\frac{3}{2}}}{\frac{1}{\sqrt [4]{c{x}^{2}+a}}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] int(1/(e*x+d)^(3/2)/(c*x^2+a)^(1/4),x)
[Out]
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Maxima [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{{\left (c x^{2} + a\right )}^{\frac{1}{4}}{\left (e x + d\right )}^{\frac{3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((c*x^2 + a)^(1/4)*(e*x + d)^(3/2)),x, algorithm="maxima")
[Out]
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Fricas [F] time = 0., size = 0, normalized size = 0. \[{\rm integral}\left (\frac{1}{{\left (c x^{2} + a\right )}^{\frac{1}{4}}{\left (e x + d\right )}^{\frac{3}{2}}}, x\right ) \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((c*x^2 + a)^(1/4)*(e*x + d)^(3/2)),x, algorithm="fricas")
[Out]
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Sympy [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{\sqrt [4]{a + c x^{2}} \left (d + e x\right )^{\frac{3}{2}}}\, dx \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/(e*x+d)**(3/2)/(c*x**2+a)**(1/4),x)
[Out]
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GIAC/XCAS [F] time = 0., size = 0, normalized size = 0. \[ \int \frac{1}{{\left (c x^{2} + a\right )}^{\frac{1}{4}}{\left (e x + d\right )}^{\frac{3}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
[In] integrate(1/((c*x^2 + a)^(1/4)*(e*x + d)^(3/2)),x, algorithm="giac")
[Out]